# IGCSE Mathematics Paper-1: Specimen Questions with Answers 171 - 173 of 324

## Question 171

Edit

### Write in Short

(a. Find the value of p.

(b) . Find the value of q.

(c) . Find the value of x.

### Explanation

Here,

(a

Now, we need to convert right hand sided base into 8.

So,

So, because multiplication of same based term will give addition of their exponent.

because base is same of all exponents.

(b)

Now, we need to convert right hand sided base into 9.

So,

So, because division of same based term will give subtraction of their exponent.

because base is same of all exponents.

(c) .

## Question 172

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### Write in Short

The bearing of a temple T on a hill from the ground G is . Find the bearing of G from T.

### Explanation

Here,

The bearing of temple from the ground is , and line TG is straight line which gives angle of .

So, needed bearing of ground from temple will be: .

## Question 173

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### Describe in Detail

Essay▾

Three points A, B and C are shown in the diagram. B is at South-East of A and South-West of C.

AC = 10 m and BC = 6 m.

(a) The length of AB

(b) The bearing of B and C from A.

### Explanation

Here,

(a) is a right angled triangle,

So, by using the formula of sides of a right-angled triangle:

, where AC = 10 m and BC = 6 m is given,

.

(b) Bearing of B and C from A:

• The true bearing to a point is the angle, which is measured in degrees in a clockwise direction from the north line.
• The bearing from one point A to another B is the direction of the line between those points.
• The principal directions are north, east, south, and west, the pact is that the direction due north is a bearing of 0 degrees, due east is 90 degrees, due south is 180 degrees, and due west is 270 degrees.

So, here, bearing of B and C from A will be and respectively which is measured as shown below:

Now, we need to find

So, we can see that which makes straight angle.

Where, is given,

So,

Now,

• So, bearing of B from A is
• Bearing of C from A is .