IGCSE Mathematics Paper-1: Specimen Questions with Answers 159 - 161 of 175
Question number: 159
Describe in Detail
Solve:
A Trapezoid Made by Different Length Lines
Solve:
(a) The perimeter,
(b) The area.
Explanation
Here,
(a) A perimeter can find by adding the length of all shapes or boundaries.
So, here, perimeter =
Where, AB = 18 cm, BC = 14 cm, CD = 12 cm, DA = 14 cm.
So, Perimeter =
(b) Area of Trapezoid ABCD = , where, a and b = two parallel sides, h = height.
So, here, a = 12 cm, b = 18 cm and h = 12 cm.
So, Area A =
Question number: 160
Describe in Detail
Solve
A Geometrical Shape Made by Lines
Find out:
(a) The perimeter,
(b) The area.
Explanation
Here,
A Geometrical Shape Made by Different Length Lines
(a) A perimeter can find by adding the length of all shapes or boundaries.
So, here, perimeter =
Where, AB = 10 cm, BC = 22 cm, CD = 10 – 6 = 4 cm, DE = 22 – 14 = 8 cm, EF = 6 cm, FA = 14 cm.
So, Perimeter =
(b) Area of ABCDEF = Area of ABGF (rectangle) + Area of EGCD (rectangle)
So, area of ABGF =
Now, area of EGCD =
So, .
Question number: 161
Describe in Detail
There is a sale of 60 % discount on a shop of clothes. Vicky bought shirts of in this sale.
(a) How much did Vicky paid?
(b) The next day, all items were sold at 70 % of the original price. How much more would Vicky have saved if he had waited until the next day to buy the shirts?
Explanation
Here,
(a) Price of shirts is and sale is of 60 %.
So, he saved.
So, he paid .
(b) Next day, all items were sold at 70 % of the original price.
So, , so he will saved more than saved in 60 % discount.