# CIE Mathematics Paper-1: Specimen Questions with Answers 1 - 4 of 175

## Question number: 1

### Write in Short

Expand the brackets and simplify

### Explanation

Here,

## Question number: 2

### Write in Short

(a) Expand the bracket and simplify the expression

(b) Factorize.

### Explanation

Here,

(a) Expression is

(b) **Factorization** is the decomposition of an object into a product of other objects or factors which will give the original object after multiplication.

So,

## Question number: 3

### Write in Short

Mention multiple of 5 and 15, which is more than 20.

### Explanation

here,

- Multiples of 5 and 25 are
- So, List Common Multiple will be
- So, 25 is multiple of both 5 and 25 which is more than 20.

## Question number: 4

### Describe in Detail

Rebeca rode to her friend’s house. She waited for her friend to get ready. Then they cycled together to school. Rebeca’s journey is shown on the grid.

(a) Work out the speed at which Rebeca cycled to her friend’s house.

(b) How long did she wait for her friend?

(c) Rebeca’s brother left home at 7: 30 am. He cycled directly to school at a constant speed of 10 kilometers per hour. Find the time at which he reached at school.

(d) How many minutes earlier than Rebeca did his brother arrive at school?

### Explanation

Here,

(a) For speed of Rebeca:

As shown in chart, time is from 7 to 8: 10 to reach at her friend’s house =

Distance = 6 km.

So, speed = **. **

(b) She waits for her friend:

As shown in chart, they go to the school at 8: 50 and she reach at her friend’s house at 8: 10.

That means she waits tor ** minutes**.

(c) Rebeca’s brother left home at 7: 30 am. He cycled at speed 10

Here, total distance of school from home = 12 km.

So, 10 km = 60 minutes

So, 12 km =? minutes

he takes to reach at school.

Now, he left home 7: 30 am, so reached at school at:

(d) Rebeca reached at school at 10: 00 am while her brother reached at school at 8: 42 am.

That means **her brother reached at school** **1 hour and 18 minutes earlier. **