CIE Physics Paper-2: Specimen Questions 12 - 17 of 20

Passage

In an experiment to find the density of some oil, a student takes the following readings.

An empty measuring cylinder

An empty measuring cylinder

In figure an empty measuring cylinder is shown.

Mass of empty measuring cylinder = 850 g

A measuring cylinder is filled by oil

A measuring cylinder is filled by oil

Figure shows a measuring cylinder is filled by some oil.

Mass of cylinder containing 600 cm3 oil = 2050 g

Question number: 12 (3 of 3 Based on Passage) Show Passage

Short Answer Question▾

Write in Short

Calculate the density of the oil.

Explanation

Density of the oil is given as,

Density=MassVolume

ρ=1200600=2gcm3

Question number: 13

Fill-Blanks▾

Boiling point of the water is ________

Answer

Explanation

1000 C

Passage

Here are two words relating to the transfer of thermal energy. (Conductor and insulator). Complete each of the following sentences by writing in the appropriate word from the lost.

Question number: 14 (1 of 3 Based on Passage) Show Passage

Short Answer Question▾

Write in Short

The electric wire is often coated by plastic, because plastic is a good electric ________.

Explanation

Insulator

The electric wire is often coated by plastic, because plastic is good electric insulator and without insulation, the electricity running in a bare cable would leap over into any other electrically conducting material it touched. With enough voltage, a human could be electrocuted. Also electrical signals would disappear and get lost, causing equipment to fail.

Question number: 15 (2 of 3 Based on Passage) Show Passage

Fill-Blanks▾

Copper metal is a good ________ of electric current.

Answer

Explanation

Conductor

Question number: 16 (3 of 3 Based on Passage) Show Passage

Fill-Blanks▾

Wood is a good ________ of electric current.

Answer

Explanation

Insulator

Question number: 17

Short Answer Question▾

Write in Short

A radioactive substance has a half-life of 22 years. How much time must pass before its activity falls to 14 of its original value?

Explanation

Half – life of radioactive substance is given as,

τ12=0.693λ

22=0.693λ

λ=0.69322=0.0315

Now, for time taken before activity falls to 14 of its original value is calculated as,

A=A0eλt

14=e(0.0315)t

ln14=(0.0315)t×lne

ln40.0315=t

t=44years

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