# CIE Mathematics Paper-1: Specimen Questions 173 - 173 of 175

## Question number: 173

Essay Question▾

### Describe in Detail

Three points A, B and C are shown in the diagram. B is at South-East of A and South-West of C.

AC = 10 m and BC = 6 m.

(a) The length of AB

(b) The bearing of B and C from A.

### Explanation

Here,

(a) is a right angled triangle,

So, by using the formula of sides of a right-angled triangle:

, where AC = 10 m and BC = 6 m is given,

.

(b) Bearing of B and C from A:

• The true bearing to a point is the angle, which is measured in degrees in a clockwise direction from the north line.
• The bearing from one point A to another B is the direction of the line between those points.
• The principal directions are north, east, south, and west, the pact is that the direction due north is a bearing of 0 degrees, due east is 90 degrees, due south is 180 degrees, and due west is 270 degrees.

So, here, bearing of B and C from A will be and respectively which is measured as shown below:

Now, we need to find

So, we can see that which makes straight angle.

Where, is given,

So,

Now,

• So, bearing of B from A is
• Bearing of C from A is .
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