CIE Mathematics Paper-1: Specimen Questions 173 - 173 of 175
Question number: 173
Describe in Detail
Three points A, B and C are shown in the diagram. B is at South-East of A and South-West of C.
AC = 10 m and BC = 6 m.
(a) The length of AB
(b) The bearing of B and C from A.
(a) is a right angled triangle,
So, by using the formula of sides of a right-angled triangle:
, where AC = 10 m and BC = 6 m is given,
(b) Bearing of B and C from A:
- The true bearing to a point is the angle, which is measured in degrees in a clockwise direction from the north line.
- The bearing from one point A to another B is the direction of the line between those points.
- The principal directions are north, east, south, and west, the pact is that the direction due north is a bearing of 0 degrees, due east is 90 degrees, due south is 180 degrees, and due west is 270 degrees.
So, here, bearing of B and C from A will be and respectively which is measured as shown below:
Now, we need to find
So, we can see that which makes straight angle.
Where, is given,
- So, bearing of B from A is
- Bearing of C from A is .