# CIE Mathematics Paper-1: Specimen Questions 133 - 133 of 175

## Question number: 133

Essay Question▾

### Describe in Detail

A straight road between P and Q is shown in the diagram. R is the point south of P and east of Q. PR = 8.3 km and QR = 4.8 km.

(a) The length of the road PQ

(b) The bearing of Q from P.

### Explanation

Here,

(a) is a right angled triangle,

So, by using the formula of sides of a right angled triangle:

, where QR = 4.8 km and PR = 8.3 km is given,

.

(b) Bearing of Q from P:

• The true bearing to a point is the angle which is measured in degrees in a clockwise direction from the north line.
• The bearing from one point P to another Q is the direction of the line between those points.
• The principal directions are north, east, south, and west, the pact is that the direction due north is a bearing of 0 degrees, due east is 90 degrees, due south is 180 degrees, and due west is 270 degrees.

So, here, bearing of Q from P will be which is measured as shown below:

• So,
• So, bearing of Q from P will be:
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