CIE Mathematics Paper-1: Specimen Questions 133 - 133 of 175
Question number: 133
Describe in Detail
A straight road between P and Q is shown in the diagram. R is the point south of P and east of Q. PR = 8.3 km and QR = 4.8 km.
(a) The length of the road PQ
(b) The bearing of Q from P.
(a) is a right angled triangle,
So, by using the formula of sides of a right angled triangle:
, where QR = 4.8 km and PR = 8.3 km is given,
(b) Bearing of Q from P:
- The true bearing to a point is the angle which is measured in degrees in a clockwise direction from the north line.
- The bearing from one point P to another Q is the direction of the line between those points.
- The principal directions are north, east, south, and west, the pact is that the direction due north is a bearing of 0 degrees, due east is 90 degrees, due south is 180 degrees, and due west is 270 degrees.
So, here, bearing of Q from P will be which is measured as shown below:
- So, bearing of Q from P will be: