CIE Mathematics Paper-1: Specimen Questions 105 - 107 of 175

Question number: 105

Short Answer Question▾

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(23)x=827 Write down the value of x.

Explanation

Here,

(23)x=827 , so here, we need same fraction in right side as left side.

So, (23)x=2×2×23×3×3(23)x=(23)3x=3.

Question number: 106

Short Answer Question▾

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Solve the equation x210=2(1x)

Explanation

Here, equation is x210=2(1x)

x210=2+2x

x22x8

x24x+2x8

x(x4)+2(x4)

(x4)(x+2)

Question number: 107

Short Answer Question▾

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The diagram shows a regular octagon and a rectangle. Calculate the values of a0andb0 .

A regular octagon and a rectangle

A regular octagon and a rectangle

Find the angles a0and b0 by using the theory of regular octagon and rectangle

Explanation

Here, octagon is regular.

So, we can find it’s exterior angle by using the formula 3600n , where n = number of sides.

In octagon number of sides = 8, so exterior angle = 36008=450.

So, as shown in figure, its interior angle a0=1800450=1350 .

Now, for angle b0 :

(I) As shown in figure: b0=900+450=1350

OR

(II) As shown in figure, total angle is 3600 , so a0+b0+rectangles900=3600

1350+b0+900=3600

b0=36002250

b0=1350

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