CIE Mathematics Paper-1: Specimen Questions 1 - 4 of 175

Question number: 1

Short Answer Question▾

Write in Short

Expand the brackets and simplify 2x2+5x(x7y)

Explanation

Here,

2x2+5x(x7y)

2x2+5x235xy

7x235xy

Question number: 2

Short Answer Question▾

Write in Short

(a) Expand the bracket and simplify the expression 5(7x+12)11x+8.

(b) Factorize 12a26a .

Explanation

Here,

(a) Expression is 5(7x+12)11x+8:

35x+6011x+8

24x+68

(b) Factorization is the decomposition of an object into a product of other objects or factors which will give the original object after multiplication.

So, 12a26a=6a(2a1).

Question number: 3

Short Answer Question▾

Write in Short

Mention multiple of 5 and 15, which is more than 20.

Explanation

here,

  • Multiples of 5 and 25 are 1×5=5and5×5=25
  • So, List Common Multiple will be 5×5=25.
  • So, 25 is multiple of both 5 and 25 which is more than 20.

Question number: 4

Essay Question▾

Describe in Detail

Rebeca rode to her friend’s house. She waited for her friend to get ready. Then they cycled together to school. Rebeca’s journey is shown on the grid.

Distance vs. Time chart – Rebeca’s Home to School

Distance vs. Time chart – Rebeca’s Home to School

Showing the grid chart of distance vs. time from a home to school and friend’s house

(a) Work out the speed at which Rebeca cycled to her friend’s house.

(b) How long did she wait for her friend?

(c) Rebeca’s brother left home at 7: 30 am. He cycled directly to school at a constant speed of 10 kilometers per hour. Find the time at which he reached at school.

(d) How many minutes earlier than Rebeca did his brother arrive at school?

Explanation

Here,

(a) For speed of Rebeca:

As shown in chart, time is from 7 to 8: 10 to reach at her friend’s house = 60+10=70minutes=1.16666667hours

Distance = 6 km.

So, speed = diatncetime=61.16666667=3.6kmh .

(b) She waits for her friend:

As shown in chart, they go to the school at 8: 50 and she reach at her friend’s house at 8: 10.

That means she waits tor 5010=40 minutes.

(c) Rebeca’s brother left home at 7: 30 am. He cycled at speed 10 kmh

Here, total distance of school from home = 12 km.

So, 10 km = 60 minutes

So, 12 km =? minutes

12×6010=72minutes he takes to reach at school.

Now, he left home 7: 30 am, so reached at school at: 7:30+72minutes=7:30+1hour&12minutes=8:30+12minutes=8:42am.

(d) Rebeca reached at school at 10: 00 am while her brother reached at school at 8: 42 am.

That means her brother reached at school (8:42+1hour=9:42+18minutes=10:00) 1 hour and 18 minutes earlier.

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